ACPI / dock: Use acpi_device_enumerated() to check if dock is present

After commit 202317a573 (ACPI / scan: Add acpi_device objects for
all device nodes in the namespace) acpi_bus_get_device() will always
return 0 for dock devices in dock_notify(), so the dock station
docking code under ACPI_NOTIFY_DEVICE_CHECK will never be executed
and docking will not work as a result of that.

Fix the problem by making dock_notify() use acpi_device_enumerated()
to check the presence of the device instead of checking the return
value of acpi_bus_get_device().

Fixes: 202317a573 (ACPI / scan: Add acpi_device objects for all device nodes in the namespace)
Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>
This commit is contained in:
Rafael J. Wysocki 2014-02-10 13:44:20 +01:00
parent b28a960c42
commit 0a8e5c3d5f

View file

@ -609,7 +609,7 @@ static int handle_eject_request(struct dock_station *ds, u32 event)
static void dock_notify(struct dock_station *ds, u32 event)
{
acpi_handle handle = ds->handle;
struct acpi_device *ad;
struct acpi_device *adev = NULL;
int surprise_removal = 0;
/*
@ -632,7 +632,8 @@ static void dock_notify(struct dock_station *ds, u32 event)
switch (event) {
case ACPI_NOTIFY_BUS_CHECK:
case ACPI_NOTIFY_DEVICE_CHECK:
if (!dock_in_progress(ds) && acpi_bus_get_device(handle, &ad)) {
acpi_bus_get_device(handle, &adev);
if (!dock_in_progress(ds) && !acpi_device_enumerated(adev)) {
begin_dock(ds);
dock(ds);
if (!dock_present(ds)) {