x86: fix initialization of 'l' bit in ldt descriptors

Make sure that fill_ldt() initializes the 'l' bit in the descriptor.
It always sets it to 0, ignoring 'lm' in user_desc, preserving original
x86_64 behaviour.

Previously it was leaving 'l' uninitialized.

Signed-off-by: Jeremy Fitzhardinge <jeremy.fitzhardinge@citrix.com>
Cc: Glauber de Oliveira Costa <gcosta@redhat.com>
Signed-off-by: Ingo Molnar <mingo@elte.hu>
Cc: Glauber de Oliveira Costa <gcosta@redhat.com>
This commit is contained in:
Jeremy Fitzhardinge 2008-07-27 08:42:32 -07:00 committed by Ingo Molnar
parent b56afe1d41
commit 64f53a0492

View file

@ -24,6 +24,11 @@ static inline void fill_ldt(struct desc_struct *desc,
desc->d = info->seg_32bit;
desc->g = info->limit_in_pages;
desc->base2 = (info->base_addr & 0xff000000) >> 24;
/*
* Don't allow setting of the lm bit. It is useless anyway
* because 64bit system calls require __USER_CS:
*/
desc->l = 0;
}
extern struct desc_ptr idt_descr;