GDScript: Fix error message for Lua-style dictionary
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1 changed files with 2 additions and 2 deletions
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@ -2731,12 +2731,12 @@ GDScriptParser::ExpressionNode *GDScriptParser::parse_dictionary(ExpressionNode
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switch (dictionary->style) {
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case DictionaryNode::LUA_TABLE:
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if (key != nullptr && key->type != Node::IDENTIFIER && key->type != Node::LITERAL) {
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push_error("Expected identifier or string as LUA-style dictionary key.");
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push_error(R"(Expected identifier or string as Lua-style dictionary key (e.g "{ key = value }").)");
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advance();
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break;
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}
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if (key != nullptr && key->type == Node::LITERAL && static_cast<LiteralNode *>(key)->value.get_type() != Variant::STRING) {
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push_error("Expected identifier or string as LUA-style dictionary key.");
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push_error(R"(Expected identifier or string as Lua-style dictionary key (e.g "{ key = value }").)");
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advance();
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break;
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}
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